Faut les factoriser niv 4ème :Merci ❤️

12

(x-3) (2x+1 + 5x-7) = (x-3) (7x-6)

(11x+6) (5x-6 + 8) = (11x+6) (5x+2)

(3x+9) (7x² - 5 + 7x-12) = (3x-9) (7x² + 7x - 17) = 3 (x-3) (7x² + 7x - 17)

(14x+5) (8x-5 + 14x+5) = 22x (14x+5)

Bonjour,

Factorise

(x-3)(2x+1+5x-7)= (x-3)(7x-6)

(11x+6)(5x-6+8)= (11x+6)(5x+2)

(3x+9)(7x²-5+7x-12)= (3x+9)(7x²+7x-17)= 3(x+3)(7x²+7x-17)

(14x+5)(8x-5+14x+5)= (14x+5)(22x)<=> 22x(14x+5)