Vous pouvez m'aider svp Mathématique calcule
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1 Réponse
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1. Réponse Anonyme
Salut !
Avant toute chose, il convient de corriger les 2 erreurs dans les exemples (A et B) de l'exercice 20 .....
A = 15x + 12 = 3(5x+4)
B = 78x² + 54x + 42x⁵ = 6x(13x + 9 + 7x⁴)
ensuite :
C = 5x - xy = x(5 - y)
D = a² + 3ab = a(a + 3b)
E = 12a + 12ab = 12a(1 + b)
F = 18 + 3a + 9 = 3a + 27 = 3(a + 9)
G = 24x - 8x² = 8x(3 - x)
H = 60x³ - 24x⁵ + 36x² = 12x(5x² - 2x⁴ + 3x)
I = 7x² - 28x⁴ + 70x³ = 7x(x - 4x³ + 10x²)
J = (5x + 2y)(5 + x) + 2(5x + 2y) = (5x + 2y)(5 + x + 2) = (5x + 2y)(7 + x)
Ex. 21 :
B = 3(x - 3) + 2x(x - 3) = (x - 3)(3 + 2x)
A = (7 - 4x)(x+4) - (x+4)(7 + 3x) = (x+4)[(7 - 4x)-(7 + 3x) = -7x(x + 4)
C = (3 -2x)(5 - x)-(3 - 2x)(7 - 4x) = (3 - 2x)[(5 - x)-(7 - 4x)] = (3 - 2x)(-2 + 3x)
D = (5 + 2x)(5 - x)-(5 + 2x) = (5 + 2x)(5 - x)-(5 + 2x)(1) = (5 + 2x)(5 - x - 1)
= (5 + 2x)(4 - x)
E = (7 - 9x)(1 + x)-3(7 - 9x) = (7 - 9x)(1 + x - 3) = (7 - 9x)(x - 2)
F = (2 + x)² + 3(2 + x) = (2 + x)(2 + x)+3(2 + x) = (2 + x)(2 + x + 3) = (2 + x)(x + 5)