Bonjour, Pourriez vous maider pour l’exercice 1 et 2 s’il vous plaît Merci a vous.

Bonjour

5x+15 = 5(x+3)

7x²-3x = x(7x-3)

7a-3a = a(7-3)

x²+4x = x(x+4)

2/3 t - 3t² = t(2/3-3t)

(3x+1)(5x-2)+(3x+1)(7x+3) = (3x+1)[(5x-2)+(7x+3) = (3x+1)(12x+1)

(3x+1)(5x-2)-(3x+1)(7x+3) = (3x+1)[(5x-2)-(7x+3)] = (3x+1)(-2x-5) = -(3x+1)(2x+5)

(3x+1)(5x-2)+5(3x+1) = (3x+1)[(5x-2)+5] = (3x+1)(5x+3)