Mathématiques

Question

Developper et réduire:
A=6x-3(x+1)²
B=-3x(x-4)²
C=(-x-7)(3-5x)

2 Réponse

  • Bonjour,

    A = 6x - 3(x + 1)²
    A = 6x - 3(x² + 2x + 1)
    A = 6x - 3x² - 6x - 3
    A = -3x² - 3

    B = -3x(x - 4)²
    B = -3x(x² - 8x + 16)
    B = -3x^3 + 24x² - 48x


    C = (-x - 7)(3 - 5x)
    C = -3x + 5x² - 21 + 35x
    C = 5x² + 32x - 21
  • A=6x-3(x+1)²
    =6x-3(x²+2x+1)
    =6x-3x²-6x+3
    =3x²+3

    B=-3x(x-4)²
    =-3x(x²-16)
    =-3x³+48x²


    C=(-x-7)(3-5x)
    =5x²+32x-21

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